Median
Lecture 09
Median
is the most appropriate measure of central tendency if the data is highly skewed. The median is the middle value of the given list of data
sorted in ascending or descending order of magnitude.
If
the amount of the number is odd, median is the most middle value.
if n is odd
If
the number of the number is even, the median is the average of the middle pair.
Median for grouped data can be obtained by the following
formula.
L1 and L2 are the lower and upper class boundaries, respectively. c is the cumulative frequency of the preceding class.
Example 3.29: A family has 7 children, aged 9, 17, 15, 12, 19,
21, and 25. What is the median?
Solution: ordering the children’s ages from least to greatest,
we get:
|
Rank |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
|
Ages
|
9 |
12 |
15 |
17 |
19 |
21 |
25 |
The number of observations (n = 7) is odd. We use the following
formula:
Example 3.30: Find the median for the following data:
|
7 |
15 |
25 |
45 |
18 |
26 |
37 |
46 |
50 |
65 |
Solution: Arrange the data in ascending order of magnitude.
|
Order |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
|
Value |
7 |
15 |
18 |
25 |
26 |
37 |
45 |
46 |
50 |
65 |
The number of observations (n = 10) is even. We use the
following formula:
Example 3.31: The following is a frequency table of the score
obtained in a statistics test. Find the median score.
|
Score |
0 |
5 |
6 |
7 |
8 |
9 |
|
No. of students |
3 |
4 |
7 |
6 |
3 |
2 |
Solution:
|
Score |
Frequency |
Cumulative frequency |
|
0 |
3 |
3 |
|
5 |
4 |
7 |
|
6 |
7 |
14 |
|
7 |
6 |
20 |
|
8 |
3 |
23 |
|
9 |
2 |
25 |
|
|
25 |
|
As the sum of frequency 25 is
odd, we are using the following formula.
Example 3.32: Find the median for the following mark distribution.
|
Mark |
10 – 19 |
20 – 29 |
30 – 39 |
40 – 49 |
50 – 59 |
60-69 |
70 – 79 |
|
No. of
students |
10 |
16 |
31 |
22 |
41 |
12 |
18 |
Solution:
|
Mark |
Class
boundaries |
f |
Cumulative
frequency |
|
10
– 19 |
9.5
– 19.5 |
10 |
10 |
|
20
– 29 |
19.5
– 29.5 |
16 |
26 |
|
30
– 39 |
29.5
– 39.5 |
31 |
57 |
|
40
– 49 |
39.5
– 49.5 |
22 |
79 |
|
50
– 59 |
49.5
– 59.5 |
41 |
120 |
|
60-69 |
59.5
– 69.5 |
12 |
132 |
|
70
- 79 |
69.5
– 79.5 |
18 |
150 |
|
|
|
150 |
|
To obtain median class, we divide total observation by 2.
Which approximately lies against 39.5–49.5.
Advantages
and limitations of Median.
Some advantages of median are given below:
i. It is simple to understand, and in some
cases it is obtained by inspection.
ii. It is the middle part of the data, and
hence it is not affected by extreme values.
iii. It is a special average used in
qualitative data.
iv. In grouped frequency distribution, it can
be graphically located by ogive.
Some limitations of the median are given below:
I. It is not based on all the observations.
ii. It is not well defined.
iii. Its capability for further mathematical
treatment is limited.
Determination
of Median Graphically
The median can be determined graphically from ogive.
This can be done in two ways.
i. Convert the frequency distribution into a
“less than” or “more than” cumulative frequency distribution.
ii. Present the data graphically in the form
of less than or more than ogive.
iii.
The total number of observations is n. Find the (n/2) value and mark it on the y-axis. Draw a
perpendicular line on the y-axis to the right (or left) to cut the object at point
A.
iv. From point A, where the ogive is cut, draw
a perpendicular on the x-axis. The point at which it touches the x-axis will be
the median.
Example 3.33: Find the median graphically of the following data.
|
Height
(cm) |
150 - 155 |
155 - 160 |
160 – 165 |
165
- 170 |
170 - 175 |
175
- 180 |
|
No.
of students |
4 |
7 |
18 |
11 |
6 |
4 |
Solution:
|
Height (cm) |
Frequency |
Height |
Cumulative frequency |
|
150 - 155 |
4 |
Less than 150 |
0 |
|
155 - 160 |
7 |
Less than155 |
4 |
|
160 – 165 |
18 |
Less than 160 |
11 |
|
165 – 170 |
11 |
Less than165 |
29 |
|
170 – 175 |
6 |
Less than 170 |
40 |
|
175 - 180 |
4 |
Less than 175 |
46 |
|
|
|
Less than 180 |
50 |
Empirical
Relation between Mean, Median and Mode
In moderately skewed distribution, a very important relationship
exists among these three measures of central tendencies. This relationship is
given by:
Example 3.34: The mean and median for a set of data are 15.60 and
14.20. Find mode.
Solution:
- Read More: Quartiles, Deciles, Percentiles











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