GEOMETRIC MEAN
Lecture 06
Introduction
The Greek philosopher Pythagoras first conceptualized the geometric mean, which applied in the following situations.
i. To determine the mean data expressed in
percentage.
ii. To determine the average of the series
that are not independent of each other.
iii. To determine the average of data expressed
in ratio.
iv. To find the average of highly skewed data.
DefinitionThe nth root of the product of n values.
Let X1, X2,..., Xn be the values of a data set. Then the geometric mean is defined as:
This formula is useful when the number of observations in given data is small. When a set of data contains a large number of observations, then we need an alternative way for computing the geometric mean. The alternative of computing the geometric mean is given as under:
Taking the advantages
of two properties of the logarithm:
When frequencies are
given, then the geometric mean can be obtained as:
Example 3. 13: Compare
the geometric and arithmetic means for the following data:
i. 4 and 6
ii. 5 and 5
iii. - 6 and 8
iv. 0 and 8
Solution:
i. The arithmetic mean of 4 and 6.
The geometric mean of 4 and 6.
ii. The arithmetic mean of 5 and 5.
The geometric mean of 5
and 5.
In this case, the arithmatic mean & geometric mean are identical.
iii. The arithmetic mean of -6 and 8.
The geometric mean of -6 and 8.
iv. The arithmetic mean of 0 and 8.
The geometric mean of 0
and 8.
Note: Don’t use a geometric
mean if you have any negative or zero values in your data.
Example 3.14: Find the
geometric mean of the marks obtained by 5 students in a term exam.
10, 30, 45,
76, 80
Solution:
|
X |
Log X
|
|
10 |
1.000 |
|
30 |
1.477 |
|
45 |
1.653 |
|
76 |
1.881 |
|
80 |
1.903 |
|
Total |
7.914 |
Example 3.15: Calculate the geometric mean for the following data.
|
Values |
15 |
25 |
35 |
40 |
50 |
|
Frequency |
5 |
20 |
40 |
10 |
4 |
Solution:
Example 3.16: Find the
geometric mean of the following frequency distribution.
|
Age
|
10 - 15 |
15 - 20 |
20 – 25 |
25- 30 |
30 - 35 |
35 - 40 |
|
No.
of person |
2 |
10 |
17 |
18 |
12 |
9 |
Solution:
Example 3.17: The profit
rate of a commercial firm increases 10% in the first quarter, 12.5% in the second, 11% in the third, and 13% in the fourth quarters, respectively. Find the average
increase.
Solution:
Average increase =
1.1155 – 1 = 0.1155
Average increase =
11.55%
MERITS
AND DEMERITS OF GEOMETRIC MEAN
Merits of Geometric
Mean
i. It is rigorously defined by proper mathematical formula.
ii. It is based on all the observations of
the data.
iii. It is suitable for average percentages and
ratios.
iv. It
is less affected by extreme values.
v. It gives equal weight to all the
observations.
Demerits
of Geometric mean
i. It is not simple to understand.
ii. It cannot be computed if any value is
zero or negative.
iii. It has limited application in the
statistical analyses.
- Read More: Harmonic Mean


















No comments:
Post a Comment