Examples on 2^k Factorial Experiment
lecture - 28
Example:
A 4 X 4
Perform complete
analysis of the data and give your interpretation of the results.
Solution: We setup our hypotheses as:
For treatment:
|
Treatment
Combination |
Yield |
Column
– I |
Column
- II |
Effects |
|
(1) |
50 |
132 |
318 |
|
|
n |
82 |
186 |
74 |
342.25 |
|
P |
72 |
32 |
54 |
182.25 |
|
np |
114 |
42 |
10 |
6.25 |
|
|
|
|
|
|
Remarks: H0 is
rejected and the effect of 4 treatment combination on potatoes yield is
significant.
Example:
An experiment is performed in order to investigate the effect of concentration
of a reactant and the presence of the catalyst of the reaction time of a
chemical process. Let the two levels of the reactant concentration be 15 %
& 25 %. The catalyst has two levels high level denoting the presence of the
catalyst and low level denoting the absence with three replicates. The data of
the experiment are shown in the table below:
|
Treatment
Combination |
Replicate |
||
|
I |
II |
III |
|
|
A
low, B low |
28 |
25 |
27 |
|
A
high, B low |
36 |
32 |
32 |
|
A
low, B high |
18 |
19 |
23 |
|
A
high, B high |
31 |
30 |
29 |
Test the effects of reactant concentration and catalyst and
their interaction.
Solution:
i. We setup our hypotheses as:
iii. The test statistic:
vi. Critical Regions:|
Treatment
Combination |
Total |
Column I |
Column II |
Effects |
|
(1) |
80 |
180 |
330 |
|
|
a |
100 |
150 |
50 |
208.33 |
|
b |
60 |
20 |
-
30 |
75 |
|
ab |
90 |
30 |
10 |
8.33 |
i. The following output was obtained from a
computer program that performed a two-factor ANOVA on a factorial experiment.
SV
d.f
S. S
M . S
F
A
1
0.322
?
?
B
?
80.554
40.2771
4.59
AB
?
?
?
?
Error
12
105.327
8.7773
Total
17
231.551
a. Fill in the blanks in the ANOVA table
b. How many levels were used for factor B?
c. How many replicates of the experiment were performed?
d. What conclusions would you draw about this experiment?
Solution:
Solution:
a. MS for factor A = 0.322
/ 1 = 0.322
d.f for factor B = 1
d.f for factor AB = 1
SSAB = SSTotal - (SSE
+ SSA+ SSB)
SSAB = 231.551 – (105.327
+ 0.322 + 80.554)
SSAB = 45.348
MSAB = SSAB / df
MSAB = 45.348 / 1
MSAB = 45.348
|
SV |
d.f
|
S.
S |
M
. S |
F |
|
A |
1 |
0.322 |
0.322 |
0.0366 |
|
B |
1 |
80.554 |
40.2771 |
4.59 |
|
AB |
1 |
45.348 |
45.348 |
5.166 |
|
Error |
12 |
105.327 |
8.7773 |
|
|
Total |
17 |
231.551 |
|
|
|
SV |
d.f |
S.
S |
M
. S |
F |
F tab |
|
A |
1 |
0.322 |
0.322 |
0.0366 |
3.18 |
|
B |
1 |
80.554 |
40.2771 |
4.59 |
3.18 |
|
AB |
1 |
45.348 |
45.348 |
5.166 |
3.18 |
|
Error |
12 |
105.327 |
8.7773 |
|
|
|
Total |
17 |
231.551 |
|
|
|
The interaction effect of AB and effect of factor B are significant.
|
df |
SS |
MS |
F |
P value |
|
|
A |
|
36.00 |
? |
? |
? |
|
B |
? |
? |
0.75 |
? |
? |
|
AB |
|
12.00 |
? |
? |
? |
|
Error |
6 |
7.50 |
? |
|
|
|
Total |
11 |
56.25 |
|
|
|
Answer the following questions:
(a). The form
of the above factorial experiment…...
(b). The statistical model for the factorial
experiment…...
(c). Find the missing values and complete the ANOVA table.
(d). Determine P values.
(e). interpret the results.
(f). How many blocks were used
Answers:
(a). 2^2 factorial experiment
(b). Statistical model:
(d) using the table
|
SV |
df |
SS |
MS |
F |
P
value |
|
A |
1 |
36.00 |
36.00 |
28.8 |
0.010 |
|
B |
1 |
0.75 |
0.75 |
0.6 |
0.100 |
|
AB |
1 |
12.00 |
12.00 |
9.6 |
0.010 |
|
Error |
6 |
7.50 |
1.25 |
|
|
|
Total |
11 |
56.25 |
|
|
|
Example:
A full-factorial design is being used to help with development of a prospective 3-D printing process for a ceramic scaffold material, in an attempt to improve the compressive strength. Three factors, each with two levels, have been tested, producing the results shown in the tables below:
|
Factor |
Levels |
|
|
0 |
1 |
|
|
A: Powder
size (nm) |
50 |
100 |
|
B: Layer
thickness (mm) |
0.3 |
0.5 |
|
C:
Scan speed (mm/min) |
100 |
300 |
Write down appropriate statistical model of the above experiment. Using ANOVA, determine the effect of powder size, Layer thickness, Scan speed, and the interaction between them.
Solution:The experiment consists 3 factors (i.e. A, B, C) and each factor have two levels, the following statistical model is used to represent the mentioned experiment.
|
|
Treatment
Combination of 3^2 Factorial Experiment |
|||||||
|
|
a0b0c0 |
a1b0c0 |
a0b1c0 |
a1b1c0 |
a0b0c1 |
a1b0c1 |
a0b1c1 |
a1b1c1 |
|
|
(1) |
a |
b |
ab |
c |
ac |
bc |
abc |
|
|
50 |
100 |
50 |
100 |
50 |
100 |
50 |
100 |
|
|
0.3 |
0.3 |
0.5 |
0.5 |
0.3 |
0.3 |
0.5 |
0.5 |
|
|
100 |
100 |
100 |
100 |
300 |
300 |
300 |
300 |
|
TC |
150.3 |
200.3 |
150.5 |
200.5 |
350.3 |
400.3 |
350.5 |
400.5 |
Now using Yates Method
|
TC |
Total |
Column
I |
Column
II |
Column
III |
Effects |
|
(1) |
150.3 |
350.6 |
701.6 |
2203.2 |
|
|
a |
200.3 |
351.0 |
1501.6 |
200 |
5000 |
|
b |
150.5 |
750.6 |
100 |
0.8 |
0.08 |
|
ab |
200.5 |
751.0 |
100 |
0 |
0 |
|
c |
350.3 |
50 |
0.4 |
800 |
8000 |
|
ac |
400.3 |
50 |
0.4 |
0 |
0 |
|
bc |
350.5 |
50 |
0 |
0 |
0 |
|
abc |
400.5 |
50 |
0 |
0 |
0 |
The interaction effects are insignificant and factor A, C are significant.
- Read More: 2^k Practice Questions
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