Balance Incomplete Block Design
(BIBD)
Lecture - 40
An incomplete block design is said to be incomplete
block design (BIBD), if
i. Each treatment is replicated at the same number of times in the (entire) design, (say rij = r ).
rt = bk = n
r = bk / t = n/t
ii.
Each pair of treatments must appear
together in the number of blocks (say
Thus the symbols t, b, r, k, and
If t = b the design is said to be symmetric design.
Properties
of BIBD
i.
The total number of observation = rt = bk = n
ii. r( k -1 ) =
iii. b => t
A BIBD exist: A necessary but not sufficient condition is
Solution: Here t = 4, b = 3, r = 2, k = 2, and
Check condition – 1:
Condition – 1 is not satisfied. It is not a BIBD.
Example: BIBD (4, 4, 3, 3, 2)
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Blocks |
Treatments
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T1 |
T2 |
T3 |
T4 |
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I |
* |
* |
* |
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II |
* |
* |
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* |
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III |
* |
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* |
* |
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IV |
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* |
* |
* |
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Blocks |
Treatments
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|||
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I |
A |
B |
C |
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II |
A |
B |
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D |
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III |
A |
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C |
D |
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IV |
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B |
C |
D |
Example: BIBD (3, 3, 2, 2, 1)
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Blocks |
Treatments |
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I |
A |
B |
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II |
B |
C
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III |
A |
C
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Example: BIBD (4, 6, 3, 2, 1)
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Blocks |
A |
B |
C |
D |
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I |
* |
* |
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II |
* |
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* |
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III |
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* |
* |
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IV |
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* |
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* |
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V |
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* |
* |
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VI |
* |
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* |
Alternatively
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Blocks |
Treatments |
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I |
A |
B |
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II |
A |
C |
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III |
B |
C |
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IV |
B |
D |
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V |
C |
D |
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VI |
A |
D |
Types
of BIBD
Symmetrical
BIBD
A BIBD is symmetrical if the number of blocks is equal to the
number of treatments that’s t = b.
We know that
r x t = b x k
as b = t
r x t = t x k
r = k
Properties
i.
Each block contains r = k treatments.
ii.
Each treatment occurs in r = k blocks.
iii. Each pair of treatment occurs in λ blocks.
iv. Each pair of blocks intersects on λ treatments.
A block design of b blocks in which each of t
treatments is a replicated r time. OR
A BIBD is said to be resolvable design, if b / r
Properties
A BIBD (t, b, r, k, λ) will be resolvable BIBD
Example: A BIBD (t = 4, b = 9, r = 3, k = 2, λ= 1
Solution: A BIBD will be resolvable if
The given BIBD is a resolvable design.
Affine
Resolvable Design
A
resolvable design is said to affine resolvable design if b = t + r -1
where:
Properties:
i. b/ r is an integer.
ii. b = t + r -1
iii. k^2 / t is an integer.
Example: A BIBD (t = 4, b = 6, r = 3, k = 2, λ = 1) is resolvable design?
Solution:
Condition
– 1: k^2 / t = 4/4 = 1 is an integer
Condition
– 2: b = t + r - 1
b = 4 + 3 - 1
b = 6
The given BIBD is affine resolvable design.
- Read More: Statistical & Analysis of BIBD
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